PSLE The figure shows taps A and B and an empty tank. At 2 p.m., tap A was turned on. Water flowed into the tank from tap A at a rate of 3.9 litres per minute. After 7 minutes, tap B was turned on. At 2.14 p.m., the tank was half filled with water.
- How many litres of water flowed out of tap B in 1 minute?
- At 2.21 p.m., what fraction of the tank was filled with water?
(a)
Volume of the tank
= 60 x 35 x 25
= 52500 mℓ
= 52.5 ℓ
Volume of the tank at 2.14 p.m. when it was half filled with water
= 52.5 ÷ 2
= 26.25 ℓ
Volume of water by Tap A for 7 min
= 7 x 3.9
= 27.3 ℓ
Duration that Tap B was turned
= 14 - 7
= 7 min
Since there was a decrease in the volume of water in the tank, water flowed out of Tap B at a faster rate than that of Tap A.
Volume of water that flowed out in 7 min
= 27.3 - 26.25
= 1.05 ℓ
Volume of water that flowed out in 1 min
= 1.05 ÷ 7
= 0.15 ℓ
Volume of water that flowed out of Tap B in 1 min
= 3.9 + 0.15
= 4.05 ℓ
(b)
Duration from 2.14 p.m. to 2.21 p.m. = 7 min
Volume of water that flowed out from 2.14 p.m. to 2.21 p.m.
= 7 x 0.15
= 1.05 ℓ
Volume of water left at 2.21 p.m.
= 26.25 - 1.05
= 25.2 ℓ
Fraction of the tank filled with water at 2.21 p.m.
=
25.252.5 =
1225
Answer(s): (a) 4.05 ℓ; (b) 1225