PSLE The figure shows taps A and B and an empty tank. At 10 p.m., tap A was turned on. Water flowed into the tank from tap A at a rate of 3.9 litres per minute. After 4 minutes, tap B was turned on. At 10.10 p.m., the tank was half filled with water.
- How many litres of water flowed out of tap B in 1 minute?
- At 10.20 p.m., what fraction of the tank was filled with water?
(a)
Volume of the tank
= 60 x 30 x 15
= 27000 mℓ
= 27 ℓ
Volume of the tank at 10.10 p.m. when it was half filled with water
= 27 ÷ 2
= 13.5 ℓ
Volume of water by Tap A for 4 min
= 4 x 3.9
= 15.6 ℓ
Duration that Tap B was turned
= 10 - 4
= 6 min
Since there was a decrease in the volume of water in the tank, water flowed out of Tap B at a faster rate than that of Tap A.
Volume of water that flowed out in 6 min
= 15.6 - 13.5
= 2.1 ℓ
Volume of water that flowed out in 1 min
= 2.1 ÷ 6
= 0.35 ℓ
Volume of water that flowed out of Tap B in 1 min
= 3.9 + 0.35
= 4.25 ℓ
(b)
Duration from 10.10 p.m. to 10.20 p.m. = 10 min
Volume of water that flowed out from 10.10 p.m. to 10.20 p.m.
= 10 x 0.35
= 3.5 ℓ
Volume of water left at 10.20 p.m.
= 13.5 - 3.5
= 10 ℓ
Fraction of the tank filled with water at 10.20 p.m.
=
1027 =
1027
Answer(s): (a) 4.25 ℓ; (b) 1027