PSLE The figure shows taps A and B and an empty tank. At 5 p.m., tap A was turned on. Water flowed into the tank from tap A at a rate of 3.3 litres per minute. After 5 minutes, tap B was turned on. At 5.13 p.m., the tank was half filled with water.
- How many litres of water flowed out of tap B in 1 minute?
- At 5.28 p.m., what fraction of the tank was filled with water?
(a)
Volume of the tank
= 60 x 30 x 15
= 27000 mℓ
= 27 ℓ
Volume of the tank at 5.13 p.m. when it was half filled with water
= 27 ÷ 2
= 13.5 ℓ
Volume of water by Tap A for 5 min
= 5 x 3.3
= 16.5 ℓ
Duration that Tap B was turned
= 13 - 5
= 8 min
Since there was a decrease in the volume of water in the tank, water flowed out of Tap B at a faster rate than that of Tap A.
Volume of water that flowed out in 8 min
= 16.5 - 13.5
= 3 ℓ
Volume of water that flowed out in 1 min
= 3 ÷ 8
= 0.375 ℓ
Volume of water that flowed out of Tap B in 1 min
= 3.3 + 0.375
= 3.675 ℓ
(b)
Duration from 5.13 p.m. to 5.28 p.m. = 15 min
Volume of water that flowed out from 5.13 p.m. to 5.28 p.m.
= 15 x 0.375
= 5.625 ℓ
Volume of water left at 5.28 p.m.
= 13.5 - 5.625
= 7.875 ℓ
Fraction of the tank filled with water at 5.28 p.m.
=
7.87527 =
724
Answer(s): (a) 3.675 ℓ; (b) 724