PSLE Albert and Riordan were paid a total of $3960 for a job they did. Albert was paid $1420 more than Riordan.
- How much was Riordan paid for the job?
- Albert and Riordan were paid based on the number of days they worked. Albert worked 2 times as many days as Riordan. Riordan was paid $5 less than Albert per day. How many days did Albert work?
(a)
Amount that Riordan was paid = 1 u
Amount that Albert was paid = 1 u + 1420
Total amount paid
= 1 u + 1 u + 1420
= 2 u + 1420
2 u + 1420 = 3960
2 u = 3960 - 1420
2 u = 2540
1 u = 2540 ÷ 2 = 1270
Amount that Riordan was paid
= 1 u
= $1270
(b)
Amount that Albert was paid
= 1 u + 1420
= 1270 + 1420
= $2690
Albert worked 2 times as many days as Riordan.
2 sets of Albert's salary = $2690
1 set of Albert's salary
= 2690 ÷ 2
= $1345
1 set of Riordan's salary = $1270
Difference between each set of Albert's and Riordan's salaries
= 1345 - 1270
= $75
Number of days in 1 set
= 75 ÷ 5
= 15
Number of days that Albert worked
= 2 x 15
= 30
Answer(s): (a) $1270; (b) 30