PSLE Sean and Gabriel were paid a total of $2590 for a job they did. Gabriel was paid $1820 less than Sean.
- How much was Gabriel paid for the job?
- Sean and Gabriel were paid based on the number of days they worked. Sean worked 3 times as many days as Gabriel. Sean was paid $25 more than Gabriel per day. How many days did Sean work?
(a)
Amount that Gabriel was paid = 1 u
Amount that Sean was paid = 1 u + 1820
Total amount paid
= 1 u + 1 u + 1820
= 2 u + 1820
2 u + 1820 = 2590
2 u = 2590 - 1820
2 u = 770
1 u = 770 ÷ 2 = 385
Amount that Gabriel was paid
= 1 u
= $385
(b)
Amount that Sean was paid
= 1 u + 1820
= 385 + 1820
= $2205
Sean worked 3 times as many days as Gabriel.
3 sets of Sean's salary = $2205
1 set of Sean's salary
= 2205 ÷ 3
= $735
1 set of Gabriel's salary = $385
Difference between each set of Sean's and Gabriel's salaries
= 735 - 385
= $350
Number of days in 1 set
= 350 ÷ 25
= 14
Number of days that Sean worked
= 3 x 14
= 42
Answer(s): (a) $385; (b) 42