PSLE
Oliver and Xavier were paid a total of $2440 for a job they did. Xavier was paid $880 less than Oliver.

1. How much was Xavier paid for the job?
2. Oliver and Xavier were paid based on the number of days they worked. Oliver worked 2 times as many days as Xavier. Oliver was paid $10 more than Xavier per day. How many days did Oliver work? 

(a)
Amount that Xavier was paid = 1 u
Amount that Oliver was paid = 1 u + 880

Total amount paid
= 1 u + 1 u + 880
= 2 u + 880

2 u + 880 = 2440
2 u = 2440 - 880
2 u = 1560

1 u = 1560 ÷ 2 = 780

Amount that Xavier was paid
= 1 u
= $780

(b)
Amount that Oliver was paid
= 1 u + 880
= 780 + 880
= $1660

Oliver worked 2 times as many days as Xavier.

2 sets of Oliver's salary = $1660

1 set of Oliver's salary
= 1660 ÷ 2
= $830

1 set of Xavier's salary = $780

Difference between each set of Oliver's and Xavier's salaries
= 830 - 780
= $50

Number of days in 1 set
= 50 ÷ 10
= 5

Number of days that Oliver worked
= 2 x 5
= 10

Answer(s): (a) $780; (b) 10