In the figure, EFGH is a parallelogram and JG = JH.
- Find ∠k.
- Find ∠l.
(a)
∠EJF = ∠EFJ (Isosceles triangle)
∠k
= 180° - 49° - 49° - 69°
= 13° (Interior angles)
(b)
∠EJF
= 180° - 49° - 49°
= 82° (Angles sum of triangle)
∠l
= 360° - 82°
= 278° (Angles at a point)
Answer(s): (a) 13°; (b) 278°