In the figure, EFGH is a parallelogram and JG = JH.
- Find ∠k.
- Find ∠l.
(a)
∠EJF = ∠EFJ (Isosceles triangle)
∠k
= 180° - 43° - 43° - 72°
= 22° (Interior angles)
(b)
∠EJF
= 180° - 43° - 43°
= 94° (Angles sum of triangle)
∠l
= 360° - 94°
= 266° (Angles at a point)
Answer(s): (a) 22°; (b) 266°