In the figure, BCDE is a parallelogram and FD = FE.
- Find ∠g.
- Find ∠h.
(a)
∠BFC = ∠BCF (Isosceles triangle)
∠g
= 180° - 39° - 39° - 68°
= 34° (Interior angles)
(b)
∠BFC
= 180° - 39° - 39°
= 102° (Angles sum of triangle)
∠h
= 360° - 102°
= 258° (Angles at a point)
Answer(s): (a) 34°; (b) 258°