In the figure, EFGH is a parallelogram and JG = JH.
- Find ∠k.
- Find ∠l.
(a)
∠EJF = ∠EFJ (Isosceles triangle)
∠k
= 180° - 41° - 41° - 70°
= 28° (Interior angles)
(b)
∠EJF
= 180° - 41° - 41°
= 98° (Angles sum of triangle)
∠l
= 360° - 98°
= 262° (Angles at a point)
Answer(s): (a) 28°; (b) 262°