In the figure, BCDE is a parallelogram and FD = FE.
- Find ∠g.
- Find ∠h.
(a)
∠BFC = ∠BCF (Isosceles triangle)
∠g
= 180° - 41° - 41° - 70°
= 28° (Interior angles)
(b)
∠BFC
= 180° - 41° - 41°
= 98° (Angles sum of triangle)
∠h
= 360° - 98°
= 262° (Angles at a point)
Answer(s): (a) 28°; (b) 262°