In the figure, EFGH is a parallelogram and JG = JH.
- Find ∠k.
- Find ∠l.
(a)
∠EJF = ∠EFJ (Isosceles triangle)
∠k
= 180° - 39° - 39° - 71°
= 31° (Interior angles)
(b)
∠EJF
= 180° - 39° - 39°
= 102° (Angles sum of triangle)
∠l
= 360° - 102°
= 258° (Angles at a point)
Answer(s): (a) 31°; (b) 258°