In the figure, BCDE is a parallelogram and FD = FE.
- Find ∠g.
- Find ∠h.
(a)
∠BFC = ∠BCF (Isosceles triangle)
∠g
= 180° - 45° - 45° - 71°
= 19° (Interior angles)
(b)
∠BFC
= 180° - 45° - 45°
= 90° (Angles sum of triangle)
∠h
= 360° - 90°
= 270° (Angles at a point)
Answer(s): (a) 19°; (b) 270°