In the figure, DEFG is a parallelogram and HF = HG.
- Find ∠j.
- Find ∠k.
(a)
∠DHE = ∠DEH (Isosceles triangle)
∠j
= 180° - 46° - 46° - 68°
= 20° (Interior angles)
(b)
∠DHE
= 180° - 46° - 46°
= 88° (Angles sum of triangle)
∠k
= 360° - 88°
= 272° (Angles at a point)
Answer(s): (a) 20°; (b) 272°