PSLE Pamela has a triangular piece of paper HJK with JH = JK, ∠HJK = 82° and ∠KLL = 70°. HLK and JLK are straight lines. She folded it along the line LM as shown.
- Find ∠n.
- Find ∠p.
(a)
Length of HJ = Length of JK
Triangle HJK is an isosceles triangle.
∠JKH
= (180° - 82°) ÷ 2
= 98° ÷ 2
= 49° (Isosceles triangle)
∠n
= 180° - 70° - 49°
= 61° (Angles sum of triangle)
(b)
∠JHK = ∠JKH = 49°
∠q
= 180° - 70° - 70°
= 40° (Angles on a straight line)
∠p
= 180° - 49° - 40°
= 91° (Angles sum of triangle)
Answer(s): (a) 61°; (b) 91°