PSLE Victoria has a triangular piece of paper BCD with CB = CD, ∠BCD = 84° and ∠DEE = 73°. BED and CED are straight lines. She folded it along the line EF as shown.
- Find ∠g.
- Find ∠h.
(a)
Length of BC = Length of CD
Triangle BCD is an isosceles triangle.
∠CDB
= (180° - 84°) ÷ 2
= 96° ÷ 2
= 48° (Isosceles triangle)
∠g
= 180° - 73° - 48°
= 59° (Angles sum of triangle)
(b)
∠CBD = ∠CDB = 48°
∠j
= 180° - 73° - 73°
= 34° (Angles on a straight line)
∠h
= 180° - 48° - 34°
= 98° (Angles sum of triangle)
Answer(s): (a) 59°; (b) 98°