PSLE Vanessa has a triangular piece of paper HJK with JH = JK, ∠HJK = 84° and ∠KLL = 72°. HLK and JLK are straight lines. She folded it along the line LM as shown.
- Find ∠n.
- Find ∠p.
(a)
Length of HJ = Length of JK
Triangle HJK is an isosceles triangle.
∠JKH
= (180° - 84°) ÷ 2
= 96° ÷ 2
= 48° (Isosceles triangle)
∠n
= 180° - 72° - 48°
= 60° (Angles sum of triangle)
(b)
∠JHK = ∠JKH = 48°
∠q
= 180° - 72° - 72°
= 36° (Angles on a straight line)
∠p
= 180° - 48° - 36°
= 96° (Angles sum of triangle)
Answer(s): (a) 60°; (b) 96°