PSLE Roshel has a triangular piece of paper HJK with JH = JK, ∠HJK = 76° and ∠KLL = 74°. HLK and JLK are straight lines. She folded it along the line LM as shown.
- Find ∠n.
- Find ∠p.
(a)
Length of HJ = Length of JK
Triangle HJK is an isosceles triangle.
∠JKH
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
∠n
= 180° - 74° - 52°
= 54° (Angles sum of triangle)
(b)
∠JHK = ∠JKH = 52°
∠q
= 180° - 74° - 74°
= 32° (Angles on a straight line)
∠p
= 180° - 52° - 32°
= 96° (Angles sum of triangle)
Answer(s): (a) 54°; (b) 96°