PSLE Abi has a triangular piece of paper ABC with BA = BC, ∠ABC = 78° and ∠CDD = 65°. ADC and BDC are straight lines. She folded it along the line DE as shown.
- Find ∠f.
- Find ∠g.
(a)
Length of AB = Length of BC
Triangle ABC is an isosceles triangle.
∠BCA
= (180° - 78°) ÷ 2
= 102° ÷ 2
= 51° (Isosceles triangle)
∠f
= 180° - 65° - 51°
= 64° (Angles sum of triangle)
(b)
∠BAC = ∠BCA = 51°
∠h
= 180° - 65° - 65°
= 50° (Angles on a straight line)
∠g
= 180° - 51° - 50°
= 79° (Angles sum of triangle)
Answer(s): (a) 64°; (b) 79°