PSLE Barbara has a triangular piece of paper DEF with ED = EF, ∠DEF = 80° and ∠FGG = 68°. DGF and EGF are straight lines. She folded it along the line GH as shown.
- Find ∠j.
- Find ∠k.
(a)
Length of DE = Length of EF
Triangle DEF is an isosceles triangle.
∠EFD
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
∠j
= 180° - 68° - 50°
= 62° (Angles sum of triangle)
(b)
∠EDF = ∠EFD = 50°
∠l
= 180° - 68° - 68°
= 44° (Angles on a straight line)
∠k
= 180° - 50° - 44°
= 86° (Angles sum of triangle)
Answer(s): (a) 62°; (b) 86°