PSLE
Mr Sher used ²₅ of his money to buy 15 passion fruits and 5 oranges. The cost of 5 passion fruits was the same as that of 4 oranges. What was the most number of oranges that Mr Sher could buy with the money he had left?
Fraction of his money that he had left
= 1 - ²₅ 
= ³₅

Let the cost of 1 passion fruit be 1 P.
Let the cost of 1 orange be 1 O.

5 P = 4 O _(x3)
15 P = 12 O

Since Mr Sher wants to buy oranges with the money he had left, 15 passion fruits will be substituted as 12 oranges.

²₅ of his money
= 15 P + 5 O
= 12 O + 5 O
= 17 O

²₅ of his money → 17 O
¹₅ of his money → ¹⁷₂ O
³₅ of his money → 3 x ¹⁷₂ O = 25¹₂ O

Maximum number of oranges he could buy with the money that he had left = 25

Answer(s): 25