PSLE
Mr Ng used ⁴₉ of his money to buy 15 passion fruits and 3 oranges. The cost of 5 passion fruits was the same as that of 2 oranges. What was the most number of oranges that Mr Ng could buy with the money he had left?
Fraction of his money that he had left
= 1 - ⁴₉ 
= ⁵₉

Let the cost of 1 passion fruit be 1 P.
Let the cost of 1 orange be 1 O.

5 P = 2 O _(x3)
15 P = 6 O

Since Mr Ng wants to buy oranges with the money he had left, 15 passion fruits will be substituted as 6 oranges.

⁴₉ of his money
= 15 P + 3 O
= 6 O + 3 O
= 9 O

⁴₉ of his money → 9 O
¹₉ of his money → ⁹₄ O
⁵₉ of his money → 5 x ⁹₄ O = 11¹₄ O

Maximum number of oranges he could buy with the money that he had left = 11

Answer(s): 11