PSLE
Mr Kok used ⁷₉ of his money to buy 12 lemons and 11 passion fruits. The cost of 4 lemons was the same as that of 3 passion fruits. What was the most number of passion fruits that Mr Kok could buy with the money he had left?
Fraction of his money that he had left
= 1 - ⁷₉ 
= ²₉

Let the cost of 1 lemon be 1 L.
Let the cost of 1 passion fruit be 1 P.

4 L = 3 P _(x3)
12 L = 9 P

Since Mr Kok wants to buy passion fruits with the money he had left, 12 lemons will be substituted as 9 passion fruits.

⁷₉ of his money
= 12 L + 11 P
= 9 P + 11 P
= 20 P

⁷₉ of his money → 20 P
¹₉ of his money → ²⁰₇ P
²₉ of his money → 2 x ²⁰₇ P = 5⁵₇ P

Maximum number of passion fruits he could buy with the money that he had left = 5

Answer(s): 5