PSLE
Mr Sher used ⁴₉ of his money to buy 15 lemons and 8 passion fruits. The cost of 5 lemons was the same as that of 3 passion fruits. What was the most number of passion fruits that Mr Sher could buy with the money he had left?
Fraction of his money that he had left
= 1 - ⁴₉ 
= ⁵₉

Let the cost of 1 lemon be 1 L.
Let the cost of 1 passion fruit be 1 P.

5 L = 3 P _(x3)
15 L = 9 P

Since Mr Sher wants to buy passion fruits with the money he had left, 15 lemons will be substituted as 9 passion fruits.

⁴₉ of his money
= 15 L + 8 P
= 9 P + 8 P
= 17 P

⁴₉ of his money → 17 P
¹₉ of his money → ¹⁷₄ P
⁵₉ of his money → 5 x ¹⁷₄ P = 21¹₄ P

Maximum number of passion fruits he could buy with the money that he had left = 21

Answer(s): 21