PSLE
Mr Heng used ⁵₇ of his money to buy 9 kiwis and 11 passion fruits. The cost of 3 kiwis was the same as that of 2 passion fruits. What was the most number of passion fruits that Mr Heng could buy with the money he had left?
Fraction of his money that he had left
= 1 - ⁵₇ 
= ²₇

Let the cost of 1 kiwi be 1 K.
Let the cost of 1 passion fruit be 1 P.

3 K = 2 P _(x3)
9 K = 6 P

Since Mr Heng wants to buy passion fruits with the money he had left, 9 kiwis will be substituted as 6 passion fruits.

⁵₇ of his money
= 9 K + 11 P
= 6 P + 11 P
= 17 P

⁵₇ of his money → 17 P
¹₇ of his money → ¹⁷₅ P
²₇ of his money → 2 x ¹⁷₅ P = 6⁴₅ P

Maximum number of passion fruits he could buy with the money that he had left = 6

Answer(s): 6