PSLE
Mr Peh used ⁵₉ of his money to buy 6 mangoes and 6 pomegranates. The cost of 2 mangoes was the same as that of 4 pomegranates. What was the most number of pomegranates that Mr Peh could buy with the money he had left?
Fraction of his money that he had left
= 1 - ⁵₉ 
= ⁴₉

Let the cost of 1 mango be 1 M.
Let the cost of 1 pomegranate be 1 P.

2 M = 4 P _(x3)
6 M = 12 P

Since Mr Peh wants to buy pomegranates with the money he had left, 6 mangoes will be substituted as 12 pomegranates.

⁵₉ of his money
= 6 M + 6 P
= 12 P + 6 P
= 18 P

⁵₉ of his money → 18 P
¹₉ of his money → ¹⁸₅ P
⁴₉ of his money → 4 x ¹⁸₅ P = 14²₅ P

Maximum number of pomegranates he could buy with the money that he had left = 14

Answer(s): 14