PSLE
Mr Sher used ³₈ of his money to buy 15 pomegranates and 8 oranges. The cost of 5 pomegranates was the same as that of 2 oranges. What was the most number of oranges that Mr Sher could buy with the money he had left?
Fraction of his money that he had left
= 1 - ³₈ 
= ⁵₈

Let the cost of 1 pomegranate be 1 P.
Let the cost of 1 orange be 1 O.

5 P = 2 O _(x3)
15 P = 6 O

Since Mr Sher wants to buy oranges with the money he had left, 15 pomegranates will be substituted as 6 oranges.

³₈ of his money
= 15 P + 8 O
= 6 O + 8 O
= 14 O

³₈ of his money → 14 O
¹₈ of his money → ¹⁴₃ O
⁵₈ of his money → 5 x ¹⁴₃ O = 23¹₃ O

Maximum number of oranges he could buy with the money that he had left = 23

Answer(s): 23