PSLE
Mr Ee used ⁵₈ of his money to buy 9 chikoos and 11 passion fruits. The cost of 3 chikoos was the same as that of 2 passion fruits. What was the most number of passion fruits that Mr Ee could buy with the money he had left?
Fraction of his money that he had left
= 1 - ⁵₈ 
= ³₈

Let the cost of 1 chikoo be 1 C.
Let the cost of 1 passion fruit be 1 P.

3 C = 2 P _(x3)
9 C = 6 P

Since Mr Ee wants to buy passion fruits with the money he had left, 9 chikoos will be substituted as 6 passion fruits.

⁵₈ of his money
= 9 C + 11 P
= 6 P + 11 P
= 17 P

⁵₈ of his money → 17 P
¹₈ of his money → ¹⁷₅ P
³₈ of his money → 3 x ¹⁷₅ P = 10¹₅ P

Maximum number of passion fruits he could buy with the money that he had left = 10

Answer(s): 10