The figure, not drawn to scale, is made up of Square D and Rectangles E and F. The area of Square D is
811 of the total area of Rectangles E and F.
14 of Square D is shaded.
15 of Rectangle E is shaded.
16 of Rectangle F is shaded. What fraction of the figure is shaded?
| |
D |
E |
F |
Comparing D and the
total of E and F |
8x1 =
8 u |
11x1 =
11 u |
| Total |
4x2 =
8 u |
5x1 =
5 u |
6x1 =
6 u |
| Shaded |
1x2 =
2 u |
1x1 =
1 u |
1x1 =
1 u |
| Unshaded |
3x2 =
6 u |
4x1 =
4 u |
5x1 =
5 u |
The area of D is repeated. Make the area of D the same. LCM of 8 and 4 is 8.
When D is 8 u, the total areas of E and F is 11 u.
Then adjust the values of E and F so that the total areas of E and F is equal to 11 u.
Shaded areasTotal area =
2 8 + 4 + 5 =
217 Answer(s):
217 
