PSLE A plot of land which had an area of 864 m
2 was divided into three portions of equal width. These portions were fenced using 179 m of fence as shown.
- Find the length of FG.
- Find the perimeter of the plot of land.
(a)
Length of the width of each portion
= 36 ÷ 3
= 12 m
Length of FG
= (179 - 36 - 36 - 28 - 28) ÷ 2
= 51 ÷ 2
= 25.5 m
(b)
Area of the biggest rectangle
= 28 x 12
= 336 m
2
Area of the medium rectangle
= 25.5 x 12
= 306 m
2 Area of the smallest rectangle
= 864 - 336 - 306
= 222 m
2 Length of the smallest rectangle
= 222 ÷ 12
= 18.5 m
Perimeter of the plot of land
= 179 - (2 x 18.5)
= 179 - 37
= 142 m
Answer(s): (a) 25.5 m
2; (b) 142 m