PSLE A plot of land which had an area of 2466 m
2 was divided into three portions of equal width. These portions were fenced using 301 m of fence as shown.
- Find the length of TU.
- Find the perimeter of the plot of land.
(a)
Length of the width of each portion
= 54 ÷ 3
= 18 m
Length of TU
= (301 - 54 - 54 - 50 - 50) ÷ 2
= 93 ÷ 2
= 46.5 m
(b)
Area of the biggest rectangle
= 50 x 18
= 900 m
2
Area of the medium rectangle
= 46.5 x 18
= 837 m
2 Area of the smallest rectangle
= 2466 - 900 - 837
= 729 m
2 Length of the smallest rectangle
= 729 ÷ 18
= 40.5 m
Perimeter of the plot of land
= 301 - (2 x 40.5)
= 301 - 81
= 220 m
Answer(s): (a) 46.5 m
2; (b) 220 m