PSLE A plot of land which had an area of 3080 m
2 was divided into three portions of equal width. These portions were fenced using 333 m of fence as shown.
- Find the length of TU.
- Find the perimeter of the plot of land.
(a)
Length of the width of each portion
= 60 ÷ 3
= 20 m
Length of TU
= (333 - 60 - 60 - 55 - 55) ÷ 2
= 103 ÷ 2
= 51.5 m
(b)
Area of the biggest rectangle
= 55 x 20
= 1100 m
2
Area of the medium rectangle
= 51.5 x 20
= 1030 m
2 Area of the smallest rectangle
= 3080 - 1100 - 1030
= 950 m
2 Length of the smallest rectangle
= 950 ÷ 20
= 47.5 m
Perimeter of the plot of land
= 333 - (2 x 47.5)
= 333 - 95
= 238 m
Answer(s): (a) 51.5 m
2; (b) 238 m