PSLE A plot of land which had an area of 1920 m
2 was divided into three portions of equal width. These portions were fenced using 265 m of fence as shown.
- Find the length of BC.
- Find the perimeter of the plot of land.
(a)
Length of the width of each portion
= 48 ÷ 3
= 16 m
Length of BC
= (265 - 48 - 48 - 43 - 43) ÷ 2
= 83 ÷ 2
= 41.5 m
(b)
Area of the biggest rectangle
= 43 x 16
= 688 m
2
Area of the medium rectangle
= 41.5 x 16
= 664 m
2 Area of the smallest rectangle
= 1920 - 688 - 664
= 568 m
2 Length of the smallest rectangle
= 568 ÷ 16
= 35.5 m
Perimeter of the plot of land
= 265 - (2 x 35.5)
= 265 - 71
= 194 m
Answer(s): (a) 41.5 m
2; (b) 194 m