PSLE A plot of land which had an area of 1218 m
2 was divided into three portions of equal width. These portions were fenced using 211 m of fence as shown.
- Find the length of NP.
- Find the perimeter of the plot of land.
(a)
Length of the width of each portion
= 42 ÷ 3
= 14 m
Length of NP
= (211 - 42 - 42 - 34 - 34) ÷ 2
= 59 ÷ 2
= 29.5 m
(b)
Area of the biggest portion
= 34 x 14
= 476 m
2
Area of the middle portion
= 29.5 x 14
= 413 m
2 Area of the smallest portion
= 1218 - 476 - 413
= 329 m
2 Length of the smallest portion
= 329 ÷ 14
= 23.5 m
Perimeter of the plot of land
= 211 - (2 x 23.5)
= 211 - 47
= 164 m
Answer(s): (a) 29.5 m
2; (b) 164 m