PSLE A plot of land which had an area of 1144 m
2 was divided into three portions of equal width. These portions were fenced using 201 m of fence as shown.
- Find the length of XY.
- Find the perimeter of the plot of land.
(a)
Length of the width of each portion
= 39 ÷ 3
= 13 m
Length of XY
= (201 - 39 - 39 - 32 - 32) ÷ 2
= 59 ÷ 2
= 29.5 m
(b)
Area of the biggest portion
= 32 x 13
= 416 m
2
Area of the middle portion
= 29.5 x 13
= 383.5 m
2 Area of the smallest portion
= 1144 - 416 - 383.5
= 344.5 m
2 Length of the smallest portion
= 344.5 ÷ 13
= 26.5 m
Perimeter of the plot of land
= 201 - (2 x 26.5)
= 201 - 53
= 148 m
Answer(s): (a) 29.5 m
2; (b) 148 m