Eric bought 26 more cards than Tim and Tim bought 26 cards more than Dylan. The total number of cards Eric and Tim bought was 5 times the number of cards Dylan bought.
- How many cards does Eric need to give Tim so that they have the same number of cards?
- How many cards did all three of them have altogether?
(a)
Since Eric had 26 cards more than Tim, Eric needed to give half of his extra cards to Tim.
Number of cards that Eric needs to give to Tim
= 26 ÷ 2
= 13
(b)
Number of cards that Dylan bought = 1 u
Number of cards that Tim bought = 1 u + 26
Number of cards that Eric bought
= 1 u + 26 + 26
= 1 u + 52
Number of cards that Tim and Eric bought
= 1 u + 26 + 1 u + 52
= 2 u + 78
Total number of cards that Eric and Tim bought is 5 times the number that Dylan bought.
Number of cards that Tim and Eric bought = 5 u
5 u = 2 u + 78
5 u - 2 u = 78
3 u = 78
1 u = 78 ÷ 3 = 26
Total number of cards
= 5 u + 1 u
= 6 u
= 6 x 26
= 156
Answer(s): (a) 13; (b) 156
