John bought 26 more coins than Michael and Michael bought 22 coins more than Caden. The total number of coins John and Michael bought was 9 times the number of coins Caden bought.
- How many coins does John need to give Michael so that they have the same number of coins?
- How many coins did all three of them have altogether?
(a)
Since John had 26 coins more than Michael, John needed to give half of his extra coins to Michael.
Number of coins that John needs to give to Michael
= 26 ÷ 2
= 13
(b)
Number of coins that Caden bought = 1 u
Number of coins that Michael bought = 1 u + 22
Number of coins that John bought
= 1 u + 22 + 26
= 1 u + 48
Number of coins that Michael and John bought
= 1 u + 22 + 1 u + 48
= 2 u + 70
Total number of coins that John and Michael bought is 9 times the number that Caden bought.
Number of coins that Michael and John bought = 9 u
9 u = 2 u + 70
9 u - 2 u = 70
7 u = 70
1 u = 70 ÷ 7 = 10
Total number of coins
= 9 u + 1 u
= 10 u
= 10 x 10
= 100
Answer(s): (a) 13; (b) 100
