Eric bought 24 more buttons than Luis and Luis bought 11 buttons more than Rael. The total number of buttons Eric and Luis bought was 4 times the number of buttons Rael bought.
- How many buttons does Eric need to give Luis so that they have the same number of buttons?
- How many buttons did all three of them have altogether?
(a)
Since Eric had 24 buttons more than Luis, Eric needed to give half of his extra buttons to Luis.
Number of buttons that Eric needs to give to Luis
= 24 ÷ 2
= 12
(b)
Number of buttons that Rael bought = 1 u
Number of buttons that Luis bought = 1 u + 11
Number of buttons that Eric bought
= 1 u + 11 + 24
= 1 u + 35
Number of buttons that Luis and Eric bought
= 1 u + 11 + 1 u + 35
= 2 u + 46
Total number of buttons that Eric and Luis bought is 4 times the number that Rael bought.
Number of buttons that Luis and Eric bought = 4 u
4 u = 2 u + 46
4 u - 2 u = 46
2 u = 46
1 u = 46 ÷ 2 = 23
Total number of buttons
= 4 u + 1 u
= 5 u
= 5 x 23
= 115
Answer(s): (a) 12; (b) 115
