Elyse was saving money to buy pens. She saved $3 every 8 days. After saving for 104 days, she went to buy pens that were on sale.
- What was the most number of pens she could buy?
- Elyse wanted to buy 34 pens. How much more did she need to save?
(a)
Number of sets of 8 days
= 104 ÷ 8
= 13
Amount that Elyse saved in 104 days
= 13 x 3
= $39
Maximum number of sets of 5 pens that Elyse could buy
= 39 ÷ 8
= 4 r $7
Remaining amount left after buying sets of 5 pens = $7
Maximum number of sets of 3 pens that Elyse could buy with $7
= 7 ÷ 5
= 1 r $2
Remaining amount left after buying sets of 3 pens = $2
Maximum number of pens that Elyse could buy with $2
= 2 ÷ 2
= 1
Most number of pens that Elyse could buy
= 4 x 5 + 1 x 3 + 1
= 20 + 3 + 1
= 24
(b)
Number of sets of 5 pens that Elyse could buy
= 34 ÷ 5
= 6 r 4
Number of sets of 3 pens that Elyse could buy
= 4 ÷ 3
= 1 r 1
Number of individual pens that Elyse could buy = 1
Amount that Elyse needed to buy 34 pens
= 6 x 8 + 1 x 5 + 2
= 48 + 5 + 2
= $55
Amount that Elyse needed to save more
= 55 - 39
= $16
Answer(s): (a) 24; (b) $16