A confectionery sells apple sandwiches and banana sandwiches.
| Apple sandwiches |
Banana sandwiches |
| 7 for $4.70 |
5 for $4.60 |
Penelope bought an equal number of apple sandwiches and banana sandwiches. She paid $26.10 more for the banana sandwiches and the apple sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Penelope bought an equal number of apple sandwiches and banana sandwiches. Make the number of apple sandwiches and banana sandwiches the same. LCM of 7 and 5 is 35.
Number of sets of 7 in 35
= 35 ÷ 7
= 5
Cost of 1 set of 35 apple sandwiches
= 5 x 4.70
= $23.50
Number of sets of 5 in 35
= 35 ÷ 5
= 7
Cost of 1 set of 35 banana sandwiches
= 7 x 4.60
= $32.20
Amount that Penelope paid more for 1 set of 35 banana sandwiches than 1 set of 35 apple sandwiches
= 32.20 - 23.50
= $8.70
Number of sets of $8.70
= 26.10 ÷ 8.70
= 3
Total number of sandwiches in 1 set of 35 banana sandwiches and 35 apple sandwiches
= 2 x 35
= 70
Number of sandwiches that Penelope bought
= 3 x 70
= 210
(b)
Cost of sandwiches in 1 set of 35 banana sandwiches and 35 apple sandwiches
= 23.50 + 32.20
= $55.70
Total amount that Penelope spent altogether
= 3 x 55.70
= $167.10
Answer(s): (a) 210 ; (b) $167.10
