A confectionery sells apple croissants and cherry croissants.
| Apple croissants |
Cherry croissants |
| 6 for $2.10 |
5 for $2.80 |
Tiffany bought an equal number of apple croissants and cherry croissants. She paid $44.10 more for the cherry croissants and the apple croissants.
- How many croissants did she buy?
- How much did she spend altogether?
(a)
Tiffany bought an equal number of apple croissants and cherry croissants. Make the number of apple croissants and cherry croissants the same. LCM of 6 and 5 is 30.
Number of sets of 6 in 30
= 30 ÷ 6
= 5
Cost of 1 set of 30 apple croissants
= 5 x 2.10
= $10.50
Number of sets of 5 in 30
= 30 ÷ 5
= 6
Cost of 1 set of 30 cherry croissants
= 6 x 2.80
= $16.80
Amount that Tiffany paid more for 1 set of 30 cherry croissants than 1 set of 30 apple croissants
= 16.80 - 10.50
= $6.30
Number of sets of $6.30
= 44.10 ÷ 6.30
= 7
Total number of croissants in 1 set of 30 cherry croissants and 30 apple croissants
= 2 x 30
= 60
Number of croissants that Tiffany bought
= 7 x 60
= 420
(b)
Cost of croissants in 1 set of 30 cherry croissants and 30 apple croissants
= 10.50 + 16.80
= $27.30
Total amount that Tiffany spent altogether
= 7 x 27.30
= $191.10
Answer(s): (a) 420 ; (b) $191.10
