A confectionery sells cheese croissants and banana croissants.
| Cheese croissants |
Banana croissants |
| 4 for $3.30 |
3 for $4.10 |
Gillian bought an equal number of cheese croissants and banana croissants. She paid $19.50 more for the banana croissants and the cheese croissants.
- How many croissants did she buy?
- How much did she spend altogether?
(a)
Gillian bought an equal number of cheese croissants and banana croissants. Make the number of cheese croissants and banana croissants the same. LCM of 4 and 3 is 12.
Number of sets of 4 in 12
= 12 ÷ 4
= 3
Cost of 1 set of 12 cheese croissants
= 3 x 3.30
= $9.90
Number of sets of 3 in 12
= 12 ÷ 3
= 4
Cost of 1 set of 12 banana croissants
= 4 x 4.10
= $16.40
Amount that Gillian paid more for 1 set of 12 banana croissants than 1 set of 12 cheese croissants
= 16.40 - 9.90
= $6.50
Number of sets of $6.50
= 19.50 ÷ 6.50
= 3
Total number of croissants in 1 set of 12 banana croissants and 12 cheese croissants
= 2 x 12
= 24
Number of croissants that Gillian bought
= 3 x 24
= 72
(b)
Cost of croissants in 1 set of 12 banana croissants and 12 cheese croissants
= 9.90 + 16.40
= $26.30
Total amount that Gillian spent altogether
= 3 x 26.30
= $78.90
Answer(s): (a) 72 ; (b) $78.90
