A confectionery sells vanilla sandwiches and cranberry sandwiches.
| Vanilla sandwiches |
Cranberry sandwiches |
| 5 for $4.30 |
3 for $4.70 |
Risa bought an equal number of vanilla sandwiches and cranberry sandwiches. She paid $63.60 more for the cranberry sandwiches and the vanilla sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Risa bought an equal number of vanilla sandwiches and cranberry sandwiches. Make the number of vanilla sandwiches and cranberry sandwiches the same. LCM of 5 and 3 is 15.
Number of sets of 5 in 15
= 15 ÷ 5
= 3
Cost of 1 set of 15 vanilla sandwiches
= 3 x 4.30
= $12.90
Number of sets of 3 in 15
= 15 ÷ 3
= 5
Cost of 1 set of 15 cranberry sandwiches
= 5 x 4.70
= $23.50
Amount that Risa paid more for 1 set of 15 cranberry sandwiches than 1 set of 15 vanilla sandwiches
= 23.50 - 12.90
= $10.60
Number of sets of $10.60
= 63.60 ÷ 10.60
= 6
Total number of sandwiches in 1 set of 15 cranberry sandwiches and 15 vanilla sandwiches
= 2 x 15
= 30
Number of sandwiches that Risa bought
= 6 x 30
= 180
(b)
Cost of sandwiches in 1 set of 15 cranberry sandwiches and 15 vanilla sandwiches
= 12.90 + 23.50
= $36.40
Total amount that Risa spent altogether
= 6 x 36.40
= $218.40
Answer(s): (a) 180 ; (b) $218.40
