A confectionery sells apple sandwiches and banana sandwiches.
Apple sandwiches |
Banana sandwiches |
5 for $2.60 |
3 for $3.10 |
Gillian bought an equal number of apple sandwiches and banana sandwiches. She paid $61.60 more for the banana sandwiches and the apple sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Gillian bought an equal number of apple sandwiches and banana sandwiches. Make the number of apple sandwiches and banana sandwiches the same. LCM of 5 and 3 is 15.
Number of sets of 5 in 15
= 15 ÷ 5
= 3
Cost of 1 set of 15 apple sandwiches
= 3 x 2.60
= $7.80
Number of sets of 3 in 15
= 15 ÷ 3
= 5
Cost of 1 set of 15 banana sandwiches
= 5 x 3.10
= $15.50
Amount that Gillian paid more for 1 set of 15 banana sandwiches than 1 set of 15 apple sandwiches
= 15.50 - 7.80
= $7.70
Number of sets of $7.70
= 61.60 ÷ 7.70
= 8
Total number of sandwiches in 1 set of 15 banana sandwiches and 15 apple sandwiches
= 2 x 15
= 30
Number of sandwiches that Gillian bought
= 8 x 30
= 240
(b)
Cost of sandwiches in 1 set of 15 banana sandwiches and 15 apple sandwiches
= 7.80 + 15.50
= $23.30
Total amount that Gillian spent altogether
= 8 x 23.30
= $186.40
Answer(s): (a) 240 ; (b) $186.40