A confectionery sells cranberry sandwiches and cheese sandwiches.
| Cranberry sandwiches |
Cheese sandwiches |
| 6 for $3.30 |
4 for $4.40 |
Tiffany bought an equal number of cranberry sandwiches and cheese sandwiches. She paid $39.60 more for the cheese sandwiches and the cranberry sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Tiffany bought an equal number of cranberry sandwiches and cheese sandwiches. Make the number of cranberry sandwiches and cheese sandwiches the same. LCM of 6 and 4 is 12.
Number of sets of 6 in 12
= 12 ÷ 6
= 2
Cost of 1 set of 12 cranberry sandwiches
= 2 x 3.30
= $6.60
Number of sets of 4 in 12
= 12 ÷ 4
= 3
Cost of 1 set of 12 cheese sandwiches
= 3 x 4.40
= $13.20
Amount that Tiffany paid more for 1 set of 12 cheese sandwiches than 1 set of 12 cranberry sandwiches
= 13.20 - 6.60
= $6.60
Number of sets of $6.60
= 39.60 ÷ 6.60
= 6
Total number of sandwiches in 1 set of 12 cheese sandwiches and 12 cranberry sandwiches
= 2 x 12
= 24
Number of sandwiches that Tiffany bought
= 6 x 24
= 144
(b)
Cost of sandwiches in 1 set of 12 cheese sandwiches and 12 cranberry sandwiches
= 6.60 + 13.20
= $19.80
Total amount that Tiffany spent altogether
= 6 x 19.80
= $118.80
Answer(s): (a) 144 ; (b) $118.80
