A confectionery sells strawberry sandwiches and cheese sandwiches.
| Strawberry sandwiches |
Cheese sandwiches |
| 5 for $3.30 |
4 for $3.70 |
Min bought an equal number of strawberry sandwiches and cheese sandwiches. She paid $37.10 more for the cheese sandwiches and the strawberry sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Min bought an equal number of strawberry sandwiches and cheese sandwiches. Make the number of strawberry sandwiches and cheese sandwiches the same. LCM of 5 and 4 is 20.
Number of sets of 5 in 20
= 20 ÷ 5
= 4
Cost of 1 set of 20 strawberry sandwiches
= 4 x 3.30
= $13.20
Number of sets of 4 in 20
= 20 ÷ 4
= 5
Cost of 1 set of 20 cheese sandwiches
= 5 x 3.70
= $18.50
Amount that Min paid more for 1 set of 20 cheese sandwiches than 1 set of 20 strawberry sandwiches
= 18.50 - 13.20
= $5.30
Number of sets of $5.30
= 37.10 ÷ 5.30
= 7
Total number of sandwiches in 1 set of 20 cheese sandwiches and 20 strawberry sandwiches
= 2 x 20
= 40
Number of sandwiches that Min bought
= 7 x 40
= 280
(b)
Cost of sandwiches in 1 set of 20 cheese sandwiches and 20 strawberry sandwiches
= 13.20 + 18.50
= $31.70
Total amount that Min spent altogether
= 7 x 31.70
= $221.90
Answer(s): (a) 280 ; (b) $221.90
