A confectionery sells apricot sandwiches and cherry sandwiches.

Apricot sandwiches	Cherry sandwiches
6 for $3.10	4 for $2.80

Olivia bought an equal number of apricot sandwiches and cherry sandwiches. She paid $8.80 more for the cherry sandwiches and the apricot sandwiches.

1. How many sandwiches did she buy?
2. How much did she spend altogether?

(a)
Olivia bought an equal number of apricot sandwiches and cherry sandwiches.  Make the number of apricot sandwiches and cherry sandwiches the same.  LCM of 6 and 4 is 12.

Number of sets of 6 in 12
= 12 ÷ 6
= 2

Cost of 1 set of 12 apricot sandwiches
= 2 x 3.10
= $6.20

Number of sets of 4 in 12
= 12 ÷ 4
= 3

Cost of 1 set of 12 cherry sandwiches
= 3 x 2.80
= $8.40

Amount that Olivia paid more for 1 set of 12 cherry sandwiches than 1 set of 12 apricot sandwiches
= 8.40 - 6.20
= $2.20

Number of sets of $2.20
= 8.80 ÷ 2.20
= 4

Total number of sandwiches in 1 set of 12 cherry sandwiches and 12 apricot sandwiches
= 2 x 12
= 24

Number of sandwiches that Olivia bought
= 4 x 24
= 96

(b)
Cost of sandwiches in 1 set of 12 cherry sandwiches and 12 apricot sandwiches
= 6.20 + 8.40
= $14.60

Total amount that Olivia spent altogether
= 4 x 14.60
= $58.40

Answer(s): (a) 96 ; (b) $58.40