A confectionery sells cheese sandwiches and cranberry sandwiches.
| Cheese sandwiches |
Cranberry sandwiches |
| 6 for $2.10 |
4 for $3.90 |
Kylie bought an equal number of cheese sandwiches and cranberry sandwiches. She paid $300 more for the cranberry sandwiches and the cheese sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Kylie bought an equal number of cheese sandwiches and cranberry sandwiches. Make the number of cheese sandwiches and cranberry sandwiches the same. LCM of 6 and 4 is 12.
Number of sets of 6 in 12
= 12 ÷ 6
= 2
Cost of 1 set of 12 cheese sandwiches
= 2 x 2.10
= $4.20
Number of sets of 4 in 12
= 12 ÷ 4
= 3
Cost of 1 set of 12 cranberry sandwiches
= 3 x 3.90
= $11.70
Amount that Kylie paid more for 1 set of 12 cranberry sandwiches than 1 set of 12 cheese sandwiches
= 11.70 - 4.20
= $7.50
Number of sets of $7.50
= 300 ÷ 7.50
= 4
Total number of sandwiches in 1 set of 12 cranberry sandwiches and 12 cheese sandwiches
= 2 x 12
= 24
Number of sandwiches that Kylie bought
= 4 x 24
= 96
(b)
Cost of sandwiches in 1 set of 12 cranberry sandwiches and 12 cheese sandwiches
= 4.20 + 11.70
= $15.90
Total amount that Kylie spent altogether
= 4 x 15.90
= $63.60
Answer(s): (a) 96 ; (b) $63.60
