A confectionery sells banana sandwiches and cherry sandwiches.
Banana sandwiches |
Cherry sandwiches |
6 for $2.30 |
4 for $3.10 |
Yoko bought an equal number of banana sandwiches and cherry sandwiches. She paid $23.50 more for the cherry sandwiches and the banana sandwiches.
- How many sandwiches did she buy?
- How much did she spend altogether?
(a)
Yoko bought an equal number of banana sandwiches and cherry sandwiches. Make the number of banana sandwiches and cherry sandwiches the same. LCM of 6 and 4 is 12.
Number of sets of 6 in 12
= 12 ÷ 6
= 2
Cost of 1 set of 12 banana sandwiches
= 2 x 2.30
= $4.60
Number of sets of 4 in 12
= 12 ÷ 4
= 3
Cost of 1 set of 12 cherry sandwiches
= 3 x 3.10
= $9.30
Amount that Yoko paid more for 1 set of 12 cherry sandwiches than 1 set of 12 banana sandwiches
= 9.30 - 4.60
= $4.70
Number of sets of $4.70
= 23.50 ÷ 4.70
= 5
Total number of sandwiches in 1 set of 12 cherry sandwiches and 12 banana sandwiches
= 2 x 12
= 24
Number of sandwiches that Yoko bought
= 5 x 24
= 120
(b)
Cost of sandwiches in 1 set of 12 cherry sandwiches and 12 banana sandwiches
= 4.60 + 9.30
= $13.90
Total amount that Yoko spent altogether
= 5 x 13.90
= $69.50
Answer(s): (a) 120 ; (b) $69.50