Albert started saving part of his pocket money by putting 2 coins in a money box every day. Each coin was either a 10¢ or 20¢ coin. His mother also put on a $1 coin in the box every 7 days. The total value of the coins after 63 days was $28.20.
- How many coins were there altogether?
- How many of the coins were 20¢ coins?
Total nuber of coins that his mother put in
= 63 ÷ 7
= 9
Total number of coins that Albert saved
= 2 x 63 = 126 Total number of coins
= 9 + 126
= 135
(b)
Amount contributed by his mother
= 9 x 1
= $9
Amount that Albert saved
= 28.20 - 9
= $19.20
$1 = 100¢
$19.20 = 1920¢
Number of 20¢ coins |
Total value of 20¢ coins |
Number of 10¢ coins |
Total value of 10¢ coins |
Total value |
126
|
126 x 20 = 2520¢ |
0
|
0
|
2520¢
|
125
|
125 x 20 = 2500¢ |
1
|
1 x 10 = 10¢ |
2510¢
|
66 |
66 x 20 = 1320¢ |
60 |
60 x 10 = 600¢ |
1920¢
|
Amount that Albert saved if all he saved were 20¢ coins
= 126 x 20
= 2520
Big difference between the total values of 20¢ coins and 10¢ coins
= 2520 - 1920
= 600
Small difference between the value of 20¢ coins and 10¢ coins
= 20 - 10
= 10
Number of 10¢ coins
= 600 ÷ 10
= 60
Number of 20¢ coins
= 126 - 60
= 66
Answer(s): (a) 135; (b) 66